avand raportul molar de 1:7 => x moli de alfa si 7x moli de beta
Macidsulfonic=MC₁₀H₈SO₃=208g/mol
Mnaftalina=128g/mol
mamestec=208*8x+128*y=1664x+128y=3840g (I)
3840g amestec...................100%
16*3*8x g/mol oxigen...............20% (aici 48x de la alfa si 48*7x de la beta)
384x=3840*100/20=768g O => x=2moli => 2mol alfa si 14moli beta
mamestec=3328+128y=3840=> 128y=512 => y=4moli naftalina
avem in total 20moli amestec
Ct=ntrans*100%/nintrodus=16*100/20=80%