1.Notam cu "x" suma .
x:205= C , r
x=205c+r
r=c-1
Deci x=25c+c-1 adica 206c-1
restul <205 deci restul = [0,1,2,3,4.......,204] -> 205 termeni.
Suma caturilor=1+2+3+4+......+205=(205+1)(201+1-2)/2=206*205/2=21115
Suma=206*21115-1*205=4349485
2. x:49=c , r
y=49c+r
r=c+1
x=49c+c+1=50c+1
restul < 49
In caz ca catul =0,1,2.....,47 , rest = 1,2,3,......,48 deci exista 48 termeni
Suma de caturi=1+2+....+47=1128
Suma=1128*50+48=56448
3.a:27=c , rest 2c
a=27c+2c=a=29c
rest =2c<27 deci 2c mai mic sau egal cu 26 ! adica c< sau egal cu 13
Daca c e nenul -> c mai mare sau egal cu 1
Daca c=1,2,3.....,13 exista 13 termeni
Suma caturilor=1+2+3+.....+13=13*14/2=91
Suma =29*9=12639