[tex]\rm~Pentru ~inceput~trebuie~stabilit~domeniul~de~de.fi.ni.ti.e. \\ \\ x+4 \geq 0 \Rightarrow x \geq -4. \\ \sqrt{x+4} \geq 0 \Rightarrow x+2 \geq 0 \Rightarrow x \geq -2. \\ \\ Ridicand~ecuatia~la~patrat,~obtinem: \\ \\ x+4=x^2+4x+4 \Leftrightarrow x^2+3x=0 \Leftrightarrow x(x+3)=0 \Rightarrow x \in \{0;-3\}. \\ \\ Dar~x \geq -2 \Rightarrow x=0. \\ \\ \underline{Solutie}:~x=0.[/tex]
