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1.Stabiliti valoarea de adevar a proportiilor:
a) (-7)+(-5)<7+5=
b) (5+2-8)+(-3+4)=-1+1
c)2.(-5)=10
d)(-100).(-10)=10


Răspuns :

[tex]a)~-12\ \textless \ 12,~adevarat \\ \\ b)~0=0,~adevarat \\ \\ c)~-10=10,~fals \\ \\ d)~10=10,~adevarat[/tex]
a. [-7]-5=-12⇒-12<12⇒adevarat;
b. [-1]+1==1+1⇒adevarat;
c. 2·[-5]=-10⇒-10=10⇒fals;
d. [-100]/[-10]=100/10=10⇒10=10⇒adevarat;