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Fie mulţimile:A={2^0; 2^0+2^1;2^0+2^1+2^2:2^0+2^1+2^2+2^3;...}; B={3^0;3^0+3^1;3^0+3^1+3^2;3^0+3^1+3^2+3^3;...}. Determinaţi mulţimea A intersectat cu B.

Răspuns :

 A=(2^{0} ; 2^{0} + 2^{1} ; 2^{0}  + 2^{1} + 2^{2} ; 2^{0} +2^{1} + 2^{2}+2^{3} ;...)

 B=( 3^{0} ; 3^{0} + 3^{1} ; 3^{0}  +3^{1} +3^{2} ; 3^{0} + 3^{1}+3^{2} +3^{3} ;...)

A=(1;3;7;15) B=(1;4;13;40)

A intersectat cu B = (1)