a ∈ N a / 5 = 5 ,...... ; deci [ a /5 ] = 5
daca , de ex. a = 27 27 / 5 = 5 ,4
[ 27 /5 ] = 5
ca partea intreaga da fie 5 = a / 11 atunci a ∈[55 , 66 )
[ 4n - 3 / 11 ] = 5 def: [a ] = k daca k≤ a < k + 1
5 ≤ ( 4n -3) /11 < 5 + 1 numitor 11
5 · 11 ≤ 4n - 3 < 66
55 ≤ 4n - 3 < 66
55 + 3 ≤ 4n < 66 + 3
58 ≤ 4n < 69 impartim cu 4
58 / 4 ≤ n < 69 / 4 14 ,5 ≤ n < 17 ,25
n ∈ N
n = 15 , 16 , 17
