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cum se rezolva ecuatiile?
3x+2=-3+x,
2(x-4)-x=x+1


Răspuns :

[tex]\displaystyle a).3x+2=-3+x \\ 3x-x=-3-2 \\ 2x=-5 \\ x=- \frac{5}{2} \\ b).2(x-4)-x=x+1 \\ 2x-8-x=x+1 \\ x-8=x+1~Fals[/tex]