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Rezolvati ecuatia : (x+1) la puterea a2a + 2(x-2)(x+2)=(3x-1)(x-3)+2 .


Răspuns :

x²+2x+1+2x²-8=3x²-9x-x+3+2
12x=12
x=1
[tex] x^{2} [/tex] + 2x + 1 + 2([tex] x^{2} [/tex] - 4 ) = 3[tex] x^{2} [/tex] - 9x - 3x  + 2