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Suma a patru nr consecutive este 820

Răspuns :

a+b+c+d=820
b=a+1
c=a+2
d=a+3
a+a+1+a+2+a+3=820
4×a+1+2+3=820
4×a+6=820
4×a=814
a=814:4
a=203 rest 2