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a=√(3-2√3) la a 2 si b=√12,a-b=?

Răspuns :

[tex]a= \sqrt{(3-2 \sqrt{3} )^2} =|3-2 \sqrt{3} |=2 \sqrt{3} -3 \\ b= \sqrt{12} =2 \sqrt{3} \\ a-b=2 \sqrt{3} -3-2 \sqrt{3} =-3 \\ \boxed{a-b=-3}[/tex]