👤

Sa se calculeze: (2x-y) la a doua si (4+2x) la a doua.

Răspuns :

(2x-y)²=(2x)²-2*2x*y+y²=4x²-4xy+y²
(4+2x)²=4²+2*4*2x+(2x)²=16+16x+4x²
[tex](2x-y)^2=(2x)^2-2 \cdot 2x \cdot y+y^2=4x^2-4xy+y^2 \\ (4+2x)^2=4^2+2 \cdot 4 \cdot 2x+(2x)^2=4x^2+16x+16[/tex]