Eu ma gandesc asa:
notam cu p intersectia perpendicularei din A pe BD
PD[tex] PD^{2} = AD^{2} - AP^{2} [/tex]
PD=[tex] \sqrt{ 30^{2} - 24^{2} } [/tex]
PD=18
observam ca
<PAB=90-<PAD
<ADP=90-<PAD
=><PAB=<ADP
cos ADP=18:30
cos PAB = 24: AB
deci: AB=24*30:18=40
[tex] BD^{2} = AD^{2} + AB^{2} [/tex]
BD=[tex] \sqrt{ 30^{2} + 40^{2} } [/tex]
BD=50m
b) Aria=30*40=1200 mp
Ha=10000 mp
1200*100/10.000=12%
la pct c) imi da cu virgula...