👤

Calculati urmatoarele sume: 1+2+3+.......+47+48=

Răspuns :

Suma lui Gauss:
S= [(1+48)*48]/2=49*48/2=1176
[tex]\displaystyle 1+2+3+...+47+48= \frac{48(48+1)}{2} = \frac{48 \times 49}{2} = \frac{2352}{2} =1176[/tex]