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Daca a,b,c sunt numere naturale si a+b+c=18,iar2a+b+2c=25,atunci calculati:
(a+c)*(3a+2b+3c)


Răspuns :

a+b+c=18
2a+b+2c=25
Le adunam:
3a+2b+3c=43

2a+b+2c=25
a+b+c=18
Le scadem:
a+c=7
(a+c)(3a+2b+3c)=7*43=301