nr.1 |---------|+18|
=>=a+18
nr.2 |-------|+25|
=>=b+25
nr.3 |------|+47|
=>=c+47
=>a+18+b+25+c+47=220
=>a+b+c=220-(18+25+47)
=>a+b+c=130
=>a+18=b+25=c+47 de unde a=b+25-18=b-7
a+18=c+47 de unde a=c+47-18=c+29
b+25=c+47 de unde b=c+47-25=c+22
=>>a+b+c=130 adica c+29+c+22+c=130
=>>> 3c=130-(29+22)
=>>>c=[tex] \frac{79}{3} [/tex]
=>>>c=26,(3)
Acum nu mai am timp , dar poate poti sa ti le faci singur/a continuarea.
