a)x(x+1)=1332
x²+x-1332=0
Δ=b²-4ac=1²-4*1*(-1332)=1+5328=5329
x1(1 este indice)=(-b+√Δ)/2a=(-1+√5329)/2=(-1+73)/2=72/2=36
x2(2este indice)=(-b-√Δ)/2a=(-1-√5329)/2=(-1-73)/2=-74/2=-37
cele doua perechi de numere consecutive :36 si 37
-37 si -36
b)x(x+1)=2352
x²+x-2352=0
Δ=b²-4ac=1²-4*1*2352=1+9408=9409
x1=(-b+√Δ)/2a=(-1+√9409)/2a=(-1+97)/2=96/2=48
x2=(-b-√Δ)/2a=(-10-√9409)/2=(-1-97)/2=-98/2=-49
cele doua perechi de numare sunt :48 si 49
-49 si -48
