a+b+c+d=246
a=2n+1 iar b=2n+3 impare consecutive
c=2n ; d=2n+2 pare consecutive
a+b+c+d=246⇒ 2n+1+2n+3+2n+2n+2=246
8n+6=246
8n=246-6
8n=240
n=240:8
n=30
a=2n+1=2=61,
b=2n+3=63
c=2n=60
d=2n+2=62
numerele sunt: a=61, b=63, c=60 si d=62
suma = a+b+c+d=246
61+63+60+62=246
246=246
