[tex]\overline{ab}+\overline{bc}+\overline{ca}=\overline{abc}[/tex]
[tex]10a+b+10b+c+10c+a=100a+10b+c[/tex]
[tex]11a+11b+11c=100a+10b+c[/tex]
[tex]89a-b-10c=0[/tex]
observam ca:
b+10c≤99⇒a<2 => a=1
[tex]89-b-10c=0[/tex]
89-b trebuie sa fie multiplu de 10 => b=9
[tex]89-9-10c=0 =\ \textgreater \ c=8[/tex]
Deci a,b,c=1,9,8
19+98+81=198 ok
