[tex][\frac{3^{48}}{3^{18}}+(2^{4})^{5}+\frac{6^{23}}{6^{13}}]:[(3^{5})^{2}*(2^{2})^{5}+3^{17}*3^{13}+(2^{5})^{4}]=\\(3^{48-18}+2^{4*5}+6^{23-13}):(3^{5*2}*2^{2*5}+3^{17+13}+2^{5*4})=\\(3^{30}+2^{20}+6^{10}):(3^{10}*2^{10}+3^{30}+2^{20})=\\\frac{6^{10}}{3^{10}*2^{10}}=\\\frac{(3*2)^{10}}{3^{10}*2^{10}}=\\\frac{3^{10}*2^{10}}{3^{10}*2^{10}}=1[/tex]
