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aflati numerele a b c stiind ca sunt numere pare consecutive 5+5+a+5+b+c+5+5=103


Răspuns :

5+5+a+5+a+2+a+2+2+5+5=103
3a=103-31
3a=72
a=24
b=26
c=28
5+5+24+5+26+28+5+5=103