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(3x-6)(4x-3)=0 va rog frumos ,ajutati-ma


Răspuns :

(3x-6)(4x-3)=12x^2-9x-24x+18=12x^2-33x+18=0
Delta=1089-864=225
x1=(33-15)/24=1
x2=(33+15)/24=2