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cum se calculeaza : (^=la puterea) AJUTOR VA ROGGG!!!!
3^30+2^20+6^10


Răspuns :

[tex](3^{30}+2^{20}+6^{10}):(3^{10}*2^{10}+3^{30}+2^{20})=\\ =(3^{30}+2^{20}+6^{10}):[(3*2)^{10}+3^{30}+2^{20}]=\\ =(3^{30}+2^{20}+6^{10}):(6^{10}+3^{30}+2^{20})=1[/tex]