[tex](x^2+x)-5(x^2+x)+6\ \textless \ 0
x^2+x-5x^2-5x+6=0
-4x^2-4x+6=0 / :2
-2x^2-2x+3=0 /(-1)
2x^2+2x-3=0
[/tex]
[tex]2x^2+2x-3=0
a=2
b=2
c=-3
delta=b^2-4ac = 2^2-4*2*(-3)=4+24= \sqrt{28}=2 \sqrt{7}
x_{1}= \frac{-2+2 \sqrt{7} }{4}
x_{2}= \frac{-2-2 \sqrt{7} }{4}
[/tex]
Tabelul il ai in imagine
