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aratati ca:
a)ab+ba : ( sunt trei puncte ) 11
b)abc +bca + cab : ( sunt 3 puncte ) 3


Răspuns :

[tex]a)\overline{ab}+\overline{ba}=10a+b+10b+a=11a+11b=11(a+b) ~div~ 11[/tex]

[tex]a)\overline{abc}+\overline{bca}+\overline{cab}=100a+10b+c+100b+10c+a+100c+10a+b=[/tex]
[tex]111a+111b+111c=111(a+b+c)=3*37*(a+b+c)~div~3[/tex]