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x la puterea a doua -5x +5 < sau egal decat 1

Răspuns :

[tex]x^2-5x+5 \leq 1 \Rightarrow x^2-5x+4 \leq 0.\\ \Delta = 25-16=9 \Rightarrow \left \{ {{x_1=1} \atop {x_2=4}} \right. .\\ a=1 \ \textgreater \ 0 \Rightarrow x \in [1,4].[/tex]