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Descompuneti in factori:
a)36x³-x=
b)20x²-5y²=
c)9xy²-9x=
d)3x+18x³y³+27xla puterea a5a+y la puterea a6a=


Răspuns :

a.x(36x^2-1)
b.5(4x^2-y^2)
c.9x(y^2-1)
d.3x(1+9^5) + y^3(18x^3+y^3)
[tex]a)36x^3-x=x(36x^2-1)=x(6x-1)(6x+1)\\ b)20x^2-5y^2=5(4x^2-y^2)=5*(2x-y)(2x+y)\\ c)9xy^2-9x=9x(y^2-1)=9x(y-1)(y+1)\\ d)Asta\ nu\ stiu\ sa\ o\ fac.[/tex]