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x+(x+1)+(x+2)+(x+3)+......+(x+22)=144




Răspuns :

[tex]x+(x+1)+(x+2)+(x+3)+....+(x+22)=144\\ 23x+1+2+...+22=144\\ 23x+\frac{22*23}{2}=144\\ 23x+11*23=144\\ 23x+243=144\\ 23x=-99 x=\frac{-99}{23}[/tex]