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Aratati ca nr. a=2x5^11+3x5^12+5^13 divizibil cu 3
x= ori ^= la puterea.


Răspuns :

[tex]a=2*5^{11}+3*5^{12}+5^{13}\\ a=5^{11}(2+3*5+5^2)\\ a=5^{11}(2+15+25)\\ a=5^{11}*42=\ \textgreater \ a=5^{11}*14*3[/tex]