[tex]a= ( 5^{13}* 10^{26} )^{3} =\ \textgreater \ a= 5^{39} * 10^{78} =\ \textgreater \ a= 5^{39} *2^{78} * 5^{78} = 5^{117} * 2^{78} \\ b= ( 256^{9}* 64^{7} )^{2} * ( 4^{8} )^{3} =\ \textgreater \ b=( (2^{8})^{9} * ( 2^{6} )^{7} )^{2} * ( ( 2^{2} )^{8})^{3} =\ \textgreater \ \\
=\ \textgreater \ b= (2^{72} * 2^{42} )^{2} =\ \textgreater \ b= ( 2^{114} )^{2} * ( 2^{16} )^{3} =\ \textgreater \ b= 2^{228} * 2^{48} [/tex]
=> b=2^276
acum comparand a si b, impartim ambele cu 2^78
si trebuie doar sa comparam 5^117 cu 2^198
adica 5^117 cu 4^99 cum 5^117>4^99 => a>b
