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daca x∈ [0,2], atunci calculati lx-2l+lx+3l

Răspuns :

[tex]x\in[0,\ 2] \Longrightarrow x\ \textless \ 2|_{-2}\Longrightarrow x-2\ \textless \ 0\Longrightarrow |x-2|=-(x-2)=-x+2[/tex]    (1)

[tex]x\in[0,\ 2] \Longrightarrow x\ \textgreater \ 0|_{+3}\Longrightarrow x+3\ \textgreater \ 0\Longrightarrow |x+3|=x+3[/tex]    (2)

(1), (2) ⇒|x-2| + |x+3| = -x + 2 + x + 3 = 5



11,4 raspuns final ...|x-2| +|x+3|=|0.2-2|+|0,2+3|=|-8.2|+|3.2|=8.2+3.2=11.4