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Calculați:
[3 supra 4+2 supra3:(3 supra4- 1 supra2]×6 supra41


Răspuns :

[3/4+2/3:(3/4-1/2)] × 6/41=
=[3/4+2/3:(3/4-2/4)] × 6/41=
=(3/4+2/3:1/4) × 6/41=
=(3/4+2/3 × 4) × 6/41=
=(3/4+8/3) × 6/41=
=(9+32)/12 × 6/41=
=41/12 × 6/41=
=6/12=1/2