[tex]2x^2-x-3=0
a=2
b=-1
c=-3
delta=b^2-4ac= (-1)^2-4*2*(-3)=1+24=25
x_{1}= \frac{1+5}{4}= \frac{6}{4}= \frac{3}{2}
[/tex]
[tex] x_{2} = \frac{1-5}{4}= \frac{-4}{4}=-1 [/tex]
Conform formulei [tex]a(x-x1)(x-x2)[/tex]
Rezulta
[tex]2(x- \frac{3}{2})(x+1) [/tex]
Verificam daca este bun rezultatul ai in poza !!
