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3laputerea28 : 9la puterea¹² +3³totul la puterea¹ - 3la puterea0 •[729 : 3la puterea 5 + 3³ : (3 • 3² - 18¹)]

Răspuns :

3^28:9^12+(3^3)^1-3^0[ 729:3^5+3^3:(3x3^2-18^1)]=
=3^28:(3^2)^12+3^3-1[ 729:243+27:(3^3-18)]=
=3^28:3^2+27-1(3+27:9)=
=3^26+27-1x6=
=3^26+27-6=
=3^26+3^3-6=