Fie VABCD piramida patrulatera regulata
[tex]VO = h_{VABCD} \\ A_{b}= l^{2} \\ 16= l^{2} \\ l=4 \\ d_{patrat}=l \sqrt{2} \\ d_{patrat}=6 \sqrt{2} \\ AO= \frac{ d_{patrat} }{2} ,AO=3 \sqrt{2} \\ triunghiul VOA \\ m(A)= 90^{o} \\[/tex]⇒
conform TP ca [tex] AV^{2}= AO^{2} + VO^{2} \\ 36= AO^{2} +18 \\ AO=3 \sqrt{2} (h) \\ a_{b} = \frac{ l_{b} }{2} \\ a_{b} =2 \\ triunghiulVOM \\ m(
