Notam a nr iepurilor albi b nr celor cenusii si c nr celor cafenii
a+c=250
b+c=201
a+b=259
Adunam toate 3 operatiile si obtinem
2*a+2*b+2*c=710
2*(a+b+c)=710
a+b+c=710/2
a+b+c=305
Acum scadem din ultima operatie (a+b+c=305) primele 3 operatii (a+c=250 b+c=201 a+b=259 )
a+b+c-a-c=305-250
b=55
a+b+c-b-c=305-201
a=104
a+b+c-a-b=305-259
c=46