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a+b+c=63 numerele sunt consecutive

Răspuns :

a=?
b=a+1
c=a+1+1
a+a+1+a+1+1=63
3a+3=63
3a=63-3
3a=60
a=60:3
a=20
b=20+1
b=21
c=20+1+1
c=22
a+b+c=63     63-3=60   60+1 =61  60+2=62 60+3=63