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calculati media aritmetica si geometrica a nr x si y

x=3√3+√2    si   y=3√3-√2               b) x=√7supra√3 +1      y=√7 supra√3-1


Răspuns :

a)
[tex]ma = \frac{3 \sqrt{3}+ \sqrt{2} + 3\sqrt{3} - \sqrt{2} }{2} = \frac{6 \sqrt{3} }{2} = 3 \sqrt{3} [/tex]

[tex]mg= \sqrt{(3 \sqrt{3}+ \sqrt{2})(3 \sqrt{3}- \sqrt{2}) } = \sqrt{27-2} = \sqrt{25} = 5 [/tex]

b)
[tex]ma = \frac{ \frac{ \sqrt{7} }{ \sqrt{3} }+1 + \frac{ \sqrt{7} }{ \sqrt{3} }-1 }{2} = \frac{ \sqrt{7} }{ \sqrt{3} } [/tex]

[tex]mg = \sqrt{ (\frac{ \sqrt{7} }{ \sqrt{3} }+1)( \frac{ \sqrt{7} }{ \sqrt{3} }-1) } = \sqrt{ \frac{7}{3} -1 } = \sqrt{ \frac{4}{3} } = \frac{2 \sqrt{3} }{3} [/tex]