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Daca x(4x+23)=6, x=?

Răspuns :

[tex] x(4x+23)=6 \\ 4x²+23x-6=0 \\ ∆=529-4*4*(-6) \\ ∆=625 [tex] [tex] x_{1} = \frac{-23- \sqrt{625} }{2*4} = \frac{-23-25}{8} = -6 \\ x_{2} = \frac{-23- \sqrt{625} }{2*4} = \frac{-23+25}{8} = \frac{1}{4} [/tex]