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2√3(3-√8+5√2)-4(4+√72 )=?
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Răspuns :

6rad3-4rad6+10rad6-16-24rad2=6rad3+6rad6-4rad2-24rad2=6rad3+6rad6-28rad2
[tex] 2\sqrt{3}(3- \sqrt{8}+ 5\sqrt{2}) - 16 + 24 \sqrt{2}= \\ = ( 6\sqrt{3} - 2 \sqrt{24} + 10 \sqrt{6} ) - 16 +24 \sqrt{2}= \\ =(6 \sqrt{3} - 4 \sqrt{6} + 10 \sqrt{6})- 16 +24 \sqrt{2} = \\ = (6 \sqrt{3} + 8 \sqrt{6}) - 16 +24 \sqrt{2} [/tex]