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Suma a 7 nr naturale impare consecutive este 119. Aflati nr.       ALGEBRIC

Răspuns :

a+a+2+a+4+ a+6+a+8+a+10+a+12=119
7a+42=119
7a=77
a=77:7
a=11
[tex]a+a+2+a+4+a+6+a+8+a+10+a+12=119 \\ \\ 7a+42=119 \\ \\ 7a=77 \\ \\ \boxed{a=11} \\ \\ a+2=11+2=13 \\ a+4=11+4=15 \\ a+6=11+6=17 \\ a+8=11+8=19 \\ a+10=11+10=21 \\ a+12=11+12=23 \\ \\ \boxed{R: 11,13,15,17,19,21,23}[/tex]