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f: R⇒R
f(x)= -2x²+4x+5
ajutat-ma urgent va rog!!!(


Răspuns :

2x²+4x+5=0
a=2 b=4 c=5
Δ=b²-4ac=4²-4×2×5=-24<0

a=-2, b=4, c=5 ⇒ Δ=b²-4·a·c=4²-4·(-2)·5=16+40=56 ⇒x∨1=[tex] \frac{-4+ \sqrt{56} }{-4} [/tex], x∨2=[tex]\frac{-4-\sqrt{56}}{-4}[/tex]