👤

[tex][( \sqrt{3} - \sqrt{2} +1) ^{2} -2(3- \sqrt{6}) ]* ( \sqrt{12} + \sqrt{8} )[/tex]

Răspuns :

(3-2*rad6+2+1-2(3-rad6)*(rad12+rad8)=
(2(3-rad6)-2(3-rad6)*(rad12+rad18)=0*(rad12+rad8)=0
Pntru paranteza
[tex] ( \sqrt{3} - \sqrt{2}+1 )^{2} [/tex] folosim formula pentru
[tex] ( a - b+c )^{2} = a^{2} + b^{2} + c^{2} + 2*a*b + 2*a*c + 2*b*c [/tex] si obtinem:
(3+2+1-[tex]2* \sqrt{6} [/tex] + [tex]2* \sqrt{3} [/tex] - [tex]2* \sqrt{2} [/tex] -6 + [tex]2* \sqrt{6} [/tex])*([tex]2* \sqrt{3} [/tex] + [tex]2* \sqrt{2} [/tex])=

=([tex]2* \sqrt{3} [/tex] - [tex]2* \sqrt{2} [/tex])*([tex]2* \sqrt{3} [/tex] + [tex]2* \sqrt{2} [/tex]) =

=[tex]2*( \sqrt{3} [/tex] - [tex] \sqrt{2}) [/tex])*[tex]2* (\sqrt{3} [/tex] + [tex] \sqrt{2}) [/tex] =
=4*(3-2)=4*1=4