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A=acolada x apartine nr naturale divide 5x-1 mai mic sau egal 24

Răspuns :

5x-1≤24 <=> 5x≤25 => x≤5 = > x ∈ {0,1,2,3,4,5}
bara aia nu e divide
5x-1≤24
5x≤24-1 
5x≤23
x≤23:5
x≤4,6
x apartine nr. naturale=) x∈ acolada 0, 1, 2, 3, 4