👤

Se considera E(x)=4x²-4x+1 .Aratati ca E(x)≥0, oricare ar fii x∈ /R

Răspuns :

E(x)=4x²-4x+1;E(x)≥0=>4x²-4x+1≥0 ; 4x²-4x+1=0; delta=16-16=0 ; x1=x2= -b/2a= 4/ 8=1/2=> x apartine [1/2;+infinit)