3)b-a=1034
b:a=7rest 8 avem b=7xa+8 inlocuim in prima relatie
b-a=1034 inlocuin avem 7xa+8-a=1034
7a+a=1034-8
6a=1026
a=1026:6
a=171
din b-a=1034 avem b-171=1034
b=1034+171
b=1205
verificare
1205-171=1034
1205:171=7
1197
===8
problema 5
5) 3496:m=8 rest 176
3496=8m+176
deci 8m+176=3496
8m=3496-176
8m=3320
m=3320:8
m=415
6615=9xq
deci 9xq=6615
q=6615:9
q=735
400.002-1x2x3xn+145.404=
(400002+145404)-6xn
545406-6xn avem
6xn=545406
n=545406:6
n=90901
(8899-1528):r=7
7371:r=7
r=7371:7
r=1053
problema 6
I+II+III=1080 m
I I----I
II: I----I-----I----I
III I----I-----I----I----I----I----I----I----I
Cati m a sapat I echipa?
1080:12=90m
Cati m a sapat II echipa
90mx3=270 m
Cati m a sapat III echipa
2x(90+270)=2x360=720 m
