[tex]Q=m*c*\Delta t \\\\ Q\to caldura \ cedata \ de \ corp \ calorimetrului \\ m\to masa \ corpului \\ c\to caldura \ latenta \ de \ topire \\ \Delta \ t \to temperatura \ finala \\\\ m=3kg \\ c= 3,3*10^5 \frac{J}{kg} \\ \Delta \ t= 10^0-(-8^0)=10^0+8^0\to \boxed{18^0} \\\\ Q= 3kg* 3,3*10^5 \frac{J}{kg} *18 ^0 \\\\ Q= 9,9*10^5J *18^0 \\\\ Q= 178,2*10^5 J \\\\ \boxed{ Q=17820000J\to 1782*10^4J}[/tex]
