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[(10-3)²⁰+(28-3³)²¹]⁶

Răspuns :

[(10-3)^2+(28-3^3)^21]= =[(7^2+28-9)^21] =(49+19)^21 =68^21 Acum presupun ca atat ramane deoarece 61x61x61...61 de 21 de ori.