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[tex] \frac{x-1}{x+2}= \frac{x-3}{x+4} [/tex] ..urgent !:)

Răspuns :

( x - 1)( x + 4) = ( x + 2)( x - 3)
x² + 4x - x - 4 = x² - 3x + 2x - 6
x² + 3x - 4 = x² - x - 6
x² - x² + 3x + x - 4 + 6 = 0
4x + 2 = 0
4x = - 2
x = - 2/4
x = - 1 /2
sper ca te-am ajutat!
(x-1)(x+4)=(x+2)(x-3)
x²+4x-x-4=x²-3x+2x-6
x²+3x-4=x²-x-6
x²+3x-4-x²+x+6=0
4x+2=0
4x=-2
x=-2/4=-1/2