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descompuneti in factori   5 x ^{2}+12x+7  

Răspuns :

Egalam ecuatia cu 0, apoi dacem delta=b^2-4ac=144-140=4.
Ecuatia descomnusa in factori are formula a(x-x1)(x-x2).
Aflam radacinite: x1=-2, x2=-14/5.
                     
                   => 5(x+2)(x+14/5)