Notam laturile triunghiului cu AB,AC si BC
{AB;AC;BC}d.p.{4;5;6} rezulta ca [tex] \frac{AB}{4} = \frac{AC}{5} = \frac{BC}{6} =k
\frac{AB}{4} =k => AB=4k
[/tex]
[tex] \frac{AC}{5} =k => AC=5k
\frac{BC}{6}=k=>BC=6k [/tex]
AB+AC+BC=45
4k+5k+6k=45
15k=45
k=3
AB=4·3=12
AC=4·5=20
BC=4·6=24